w^2-10/w+2+w-4=w-3

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Solution for w^2-10/w+2+w-4=w-3 equation: 



w^2-10/w+2+w-4=w-3

We move all terms to the left:

w^2-10/w+2+w-4-(w-3)=0



Domain of the equation: w!=0

w∈R



We add all the numbers together, and all the variables

w^2+w-10/w-(w-3)-2=0

We get rid of parentheses

w^2+w-10/w-w+3-2=0

We multiply all the terms by the denominator


w^2*w+w*w-w*w+3*w-2*w-10=0

We add all the numbers together, and all the variables

w^2*w+w+w*w-w*w-10=0

Wy multiply elements

w^3+w^2-1w^2+w-10=0

We do not support ewpression: w^3

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